---
title: "L1-059 敲笨钟"
created: 2025-11-28
tags:
  - 算法
---

# L1-059 敲笨钟

## 题目 [L1-059 敲笨钟](https://pintia.cn/problem-sets/994805046380707840/exam/problems/type/7?problemSetProblemId=1111914599412858880&page=0)

![[image-be8eb075.png]]

## 思路分析

## 代码实现

```cpp
#include<bits/stdc++.h>

using namespace std;

#define endl '\n'

using ll = long long;

using ull = unsigned long long;

using PII = pair<int,int>;

using Pll = pair<ll,ll>;

int dx[4]={-1,0,1,0},dy[4]={0,1,0,-1};

const int inf = 0x3f3f3f3f;

int main(){

	ios::sync_with_stdio(0),cin.tie(0),cout.tie(0);

	int n;cin>>n;

	cin.ignore();

	while(n--){

		string s;getline(cin,s);

		int sb=s.find(',');

		int shangbanyun=sb-3;

		string sby;

		for(int j=shangbanyun;j<sb;j++){

			sby+=s[j];

		}

//		cout<<sby<<" ";

		int xb=s.find('.');

		int xiabanyun=xb-3;

		string xby;

		for(int j=xiabanyun;j<xb;j++){

			xby+=s[j];

		}

//		cout<<xby<<endl;

		string ans;

		if(sby=="ong" && xby=="ong"){

			int cnt=0;

			int pos=s.size()-1;

			while(cnt<3 && pos>=0){

				if(s[pos]==' ')	cnt++;

				pos--;

			}

			ans=s.substr(0,pos+1)+" qiao ben zhong.";

			cout<<ans<<endl;

		}

		else cout<<"Skipped"<<endl;

	}

	return 0;

}
```

## 同类题型

## 视频讲解

---
⬅️ [[L1-058 6翻了|L1-058 6翻了]] 🏠 [[00-天梯赛]] ➡️ [[L1-060 心理阴影面积|L1-060 心理阴影面积]]